Question

10 calcule
A
$3 + \sqrt{64}$
B
${7}^{2} - \sqrt{25}$
C
$\sqrt{3.8 + 1}$
D
$\sqrt{ \frac{12}{3} }$


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Answer 1

A) = 3 + √64

= 3 + 8

= 11

B) = 7² - √25

= 49 - 5

= 43

C) = √3 . 8 + 1

= √ 24 + 1

= √ 25

= 5

D) = √12/3

= √4

= 2

Answer 2

Olá!

$a) \: 3 + \sqrt{64} = \\ 3 + 8 = \\ 11 \\ \\b ) {7}^{2} - \sqrt{25} = \\ 49 - 5 = \\ 44 \\ \\ c) \: \sqrt{3 \times 8 + 1} = \\ \sqrt{24 + 1} = \\ \sqrt{25} = \\ 5 \\ \\ d) \: \sqrt{ \frac{12}{3} } = \\ \sqrt{4} = \\ 2$

Espero ter ajudado! :)