Question

(-10)³ - ⁴√2401 . ³√1000 . √256 + ⁵√-32 =​

Answer 1

$(-10)^{3} - \sqrt[4]{2401} .\sqrt[3]{1000} .\sqrt[2]{256} +\sqrt[5]{-32} =\\\\-1000 - \sqrt[4]{7^{4} } . \sqrt[3]{10^{3} } .\sqrt[2]{2^{2} .2^{2} .2^{2}.2^{2} } + \sqrt[5]{-2^{5} } =\\\\-1000 - 7 . 10.2.2.2.2+ (-2) =\\\\-1000 - 7.10.16 -2 =\\\\-1000 - 70 .16 -2 =\\\\-1000 -1120 - 2 =\\\\-1000 - 1122 = -2122$