Question

10
?
Σ (2i+3)
08. Qual o valor de i=1
a) 420
b) 440
c) 460
d) 480
e) 500


Me ajudem pfv mano ❤️

Answer 1

$\large\boxed{\begin{array}{l}\displaystyle\rm\sum_{ i=1}^{10}(2i+3)=(2\cdot1+3)+(2\cdot2+3)+(2\cdot3+3)\\\rm +(2\cdot4+3)+(2\cdot5+3)+(2\cdot6+3)+(2\cdot7+3)\\\rm +(2\cdot8+3)+(2\cdot 9+3)+(2\cdot10+3)\end{array}}$

$\large\boxed{\begin{array}{l}\displaystyle\rm\sum_{i=1}^{10}(2i+3)=(2+3)+(4+3)+(6+3)+(8+3)\\\rm +(10+3)+(12+3)+(14+3)+(16+3)+(18+3)\\\rm+(20+3)\end{array}}$

$\large\boxed{\begin{array}{l}\displaystyle\rm\sum_{i=1}^{10}(2i+3)=5+7+9+11+13+15+17+19+21+23\\\\\displaystyle\rm\sum_{i=1}^{10}(2i+3)=140\\\rm o \,gabarito\,est\acute a\,incorreto.\end{array}}$