Question

1) (x-5)=3(x+1) 2)3(x-2)=4(-x+3 3)2(x+1)-(x-1)=0

Answer 1

1) (x-5)=3(x+1)

(x - 5) = 3(x + 1)
x - 5 = 3x + 3
x - 5 - 3x = + 3
x - 3x = 3 + 5
- 2x = 8
x = 8/-2
x = - 8/2
x = - 4
 
 2)3(x-2)=4(-x+3 ????

3(x - 2) = 4(- x + 3)
3x - 6 = - 4x + 12
3x - 6 + 4x = + 12
3x + 4x = + 12 + 6
7x = 18
x = 18/7

3)2(x+1)-(x-1)=0

2(x + 1) - (x - 1) = 0  atenção no sinal
2x + 2 - X + 1 = 0
2x - x + 2 + 1 = 0
1x + 3 = 0
1x = - 3
x = - 3/1
x = - 3