Question

1-Transforme:
a) 330 K em Fahrenheit. b) 26 oC em Fahrenheit.
c) 1234 o F em Celsius. d) -74 oC em Fahrenheit. e) 884 oC em Kelvin.

Answer 1

Resposta:

$a)k - \frac{273}{5} = \frac{f - 32}{9}$

$\frac{330 - 273}{5} = \frac{f - 32}{9}$

$\frac{57}{5} = \frac{f - 32}{9}$

$\frac{11.4}{ {}^{1} } = \frac{f - 32}{9}$

$f - 32 = 102.6$

$f = 102.6 + 32$

$f = 134.6 \: fahrenheit$

$b) \frac{c}{5} = \frac{f - 32}{9}$

$\frac{26}{5} = \frac{f - 32}{9}$

$5.2 \times \frac{f - 32}{9} = \frac{5.2}{ {}^{1} } = \frac{f - 32}{9}$

$f - 32 = 46.8$

$f = 46.8 + 32$

$f = 78.8 \: fahrenheit$

$c) \frac{f - 32}{9} = \frac{c}{5}$

$\frac{1234 - 32}{9} = \frac{c}{5}$

$\frac{1202}{9} = \frac{c}{5}$

$\frac{133.5}{ {}^{1} } = \frac{c}{5}$

$c = 667.5 \: celsius$

$d) \frac{f - 32}{9} = \frac{c}{5}$

$\frac{f - 32}{9} = \frac{ - 74}{5}$

$\frac{f - 32}{9} = \frac{14.8}{ {}^{1} }$

$f - 32 = - 133.2$

$f = - 133.2 \: + \: 32$

$f - 101 {}^{0} \: fahrenheit$

$e)k = c + 273$

$k = 884 + 273$

$k = 1.157 \: kelvin$

Explicação:

ESPERO TER AJUDADO,BONS ESTUDOS.