Question

1) $7^{x}=1$

2) $25^{x-1}=125 ^{x+3}$

3 )$x^{x-1}=1$

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Answer 1

$7^x = 7^0 x = 0 ... 25^{x - 1} = 125^{x+3} (5^{2})^{x-1} = (5^{3})^{x+3} 5^{2x-2} = 5^{3x+9} 2x - 2 = 3x + 9 -x = 11 x = -11 ... x^{x-1} = 1 x^{x-1} = x^0 x - 1 = 0 x = 1$