Question

1. Somando
1+3
3+2/3
., encontramos:
1+3
d)
Subtraindo
encontramos?
10+3
10+3V3
1+10v3
cómo que resolve?

Answer 1

1) alternativa B

mmc (2,3) =>2×3=6

6/2×1 = 3
6/3×V3 = 2V3

3+2V3
6


2)alternativa A

mmc (3,5) => 3×5=15

15/3×2 = 10
15/5×V7 = 3V7

10-3V7
15