Question

1)sendo (a+b)² = 64 e ab = 12 ,calcule o valor de a² = b².

Answer 1

$\boxed{(a+b)^2 = 64}$ e $\boxed{ab = 12}$ ... $\boxed{a^2 + b^2 = ?}$

$a^2 + 2ab + b^2 = 64$

$a^2 + b^2 = 64 - 2ab$

$a^2 + b^2 = 64 -2(12)$

$a^2 + b^2 = 64 - 24$

$\boxed{\boxed{a^2+b^2 = 40}}$

Espero ter ajudado :))

Answer 2

Temos que ab= 12

(a+b)²= 64
a²+2ab+b²=64
a²+2(12)+b²=64
a²+24+b²=64
a²+b²=64-24
a²+b²=40