Question

1)seja p(x)=x5-3x2+2x determine:
A) p(-1)     B) p(o)     C) p(2)

Answer 1

a) p(1) = 1 elevado a 5 - 3.1²  + 2 . 1
    p(1) = 1 - 3 . 1 + 2
    p(1) = 1 - 3 + 2
    p(1) = 3 - 3
    p(1) = 0
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p(0) = 0 elevado a 5 - 3 .0² + 2 . 0
p(0) = 0 - 3 . 0 + 0
p(0) = 0 - 0 + 0
p(0) = 0
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p(2) = 2 elevado a 5 - 3 . 2² + 2 . 2
p(2) = 32 - 3 . 4 + 4
p(2) = 32 -12 + 4
p(2) = 36 -12
p(2) = 24