Question

1 - resolva as seguintes equações
$x {}^{2} + 7x + 12 = 0$

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Answer 1

1) x² + 7x + 12 = 0

Δ = 7² - 4 × 1 × 12

Δ = 49 - 48

Δ = 1

$x = \frac{-7+-\sqrt{1} }{2.1}$

$x= \frac{-7+- 1}{2}$

$x^{1} = \frac{-7-1}{2} = -4$

$x^{2} = \frac{-7+1}{2} =-3$