Question

1) Resolva as equações em
a) x2 -5x +4=0b) x2 +4x-5 = 0​

Answer 1

Resposta:

oii :)

Explicação passo-a-passo:

vamos lá!

a) x2 - 5x +4 = 0

a= 1

b= -5

c= 4

deltha= b2 -4ac

deltha= b2 -4acdeltha= ( -5 )2 - 4 . 1 . 4 =

deltha= b2 -4acdeltha= ( -5 )2 - 4 . 1 . 4 =deltha= 25 - 4 . 4 =

deltha= b2 -4acdeltha= ( -5 )2 - 4 . 1 . 4 =deltha= 25 - 4 . 4 =deltha= 25 - 16 =

deltha= b2 -4acdeltha= ( -5 )2 - 4 . 1 . 4 =deltha= 25 - 4 . 4 =deltha= 25 - 16 =deltha= 9

x= -b +- raiz de deltha/ 2.a

ax= 5 +- 3/2 =

ax= 5 +- 3/2 =x= 5 +- 3/2 =

x1 = 8/2 = 4

x2 = 2/2 = 1

resposta A: 4 e 1

b) x2 + 4x -5 = 0

a= 1

b= 4

c= -5

deltha= b2 -4ac

deltha= b2 -4ac deltha= ( +4 )2 -4 . 1 .-5 =

deltha= b2 -4ac deltha= ( +4 )2 -4 . 1 .-5 =deltha= 16 + 20 =

deltha= b2 -4ac deltha= ( +4 )2 -4 . 1 .-5 =deltha= 16 + 20 =deltha= 36

x= -b +- raiz de deltha/ 2.a

x= -4 +- raiz de 36/ 2.1 =

x1= -4 + 6/ 2 = 2/2 = 1

x2= -4 -6/ 2 = -10/2 = -5

resultado da B= 1 e -5

espero ter ajudado! ♡