Question

1) Resolva a equação.

Answer 1

Resposta:

Resolvendo o determinante temos

x² - 5x  = - 6

x² - 5x + 6 = 0

ax² + bx + c  = 0

a = 1

b = - 5

c = 0

$x = \dfrac{-\,b\, \pm\, \sqrt{b^{2} - \. 4ac} }{2a} = \dfrac{-\,(-\,5\, \pm\, \sqrt{(-5^{2} - \. 4 \times 1 \times 6} }{2\times 1} = \dfrac{+ 5\, \pm\, \sqrt{25 - 24} }{2}$

$x = \dfrac{+ 5\, \pm\, \sqrt{1} }{2} = \dfrac{+ 5\, \pm\, 1 }{2}$

$x_1 = \dfrac{+5\, + 1 }{2} = \dfrac{6 }{2} = 3$

$x_2 = \dfrac{+5\, - 1 }{2} = \dfrac{4 }{2} = 2$

S = { 2; 3 }