Question

1) Resolva 2x²-3x+1=0

Answer 1

Resposta:

$2x^{2} -3x+1=0\\ \\ coeficientes:\\ a=2\\ b=-3\\ c=1\\ \\ delta=b^{2} -4.a.c\\ \\ delta=(-3)^{2} -4*2*1\\ \\ delta=9-8\\ \\ delta=1\\ \\ x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-(-3)+-\sqrt{1} }{2*2} \\ \\ x=\frac{3+-1}{4} \\ \\ x'=\frac{3+1}{4} =\frac{4}{4} =1\\ \\ x''=\frac{3-1}{4} =\frac{2}{4} =\frac{1}{2} \\ \\ \\ S\left \{ {{1;~\frac{1}{2} } {}} \}$