Question

1) Por tentativas, resolva:

A) √522        B) √3025

C)√1728       D)√10648

Answer 1

A) √522 =  √2.3.87                                522 | 2
                                                              261 | 3
                                                                87 ! 87

B) √3025 = √5² . 11² = 5 . 11 = 55         3025 | 5
                                                                 605| 5
                                                                 121| 11
                                                                   11\ 11
C) √1728 = √  2^6 . 3³                             1728| 2
     = 2³.3√3 = 24√3                                    864| 2
                                                                  432| 2
                                                                   216| 2
                                                                   108| 2
                                                                     54| 2
                                                                      27|3
                                                                       9| 3
                                                                       3|3