Question

1- O ponto médio do segmento AB sendo: A (-2, 5) e B (-8, 7) é:

Answer 1

$\large\boxed{\begin{array}{l}\underline{\tt Ponto~m\acute edio~de~um~segmento}\\\sf Dado~os~pontos~A(x_A,y_A)~e~B(x_B,y_B)\\\sf o~ponto~m\acute edio~de~A~e~B\\\sf\acute e~d~\!\!efinido~por~M(x_M,y_M)~tal~que\\\huge\boxed{\boxed{\boxed{\boxed{\sf x_M=\dfrac{x_A+x_B}{2}}}}}~e~\huge\boxed{\boxed{\boxed{\boxed{\sf y_M=\dfrac{y_A+y_B}{2}}}}}\end{array}}$

$\large\boxed{\begin{array}{l}\tt dados\begin{cases}\rm A(-2,5)\longrightarrow x_A=-2~e~y_A=5\\\rm B(-8,7)\longrightarrow x_B=-8~e~y_B=7\end{cases}\\\underline{\boldsymbol{Soluc_{\!\!,}\tilde ao\!:}}\\\sf x_M=\dfrac{x_A+x_B}{2}\\\\\sf x_M=\dfrac{-2-8}{2}=-\dfrac{10}{2}=-5\\\\\sf y_M=\dfrac{y_A+y_B}{2}\\\\\sf y_M=\dfrac{5+7}{2}=\dfrac{12}{2}=6\\\sf logo\\\huge\boxed{\boxed{\boxed{\boxed{\sf M(-5,6)}}}} \end{array}}$