Question

1) log (3X) + log 2 = log 6 - log 2
calcule a sentença sendo X a solução da equação dada
X² - X-⁴​

Answer 1

Resposta:

log (3x)+log (2) = log (6) -log (2)

3x*2=6/2

3x=(6/4)

x=6/12

x=1/2

x²-x⁻⁴ =x²-1/x⁴ =(1/2)² -(1/2)⁻⁴ =1/4 -16 = -63/4

Answer 2

$log(3x) + log(2) \\ = log(6) - log(2) \\ log(2.3x) = log( \frac{6}{2} )$

$6x=3 \\ x=\frac{3\div3}{6\div3}$

$\boxed{x=\frac{1}{2}}$

${x}^{2}-{x}^{-4}={(\frac{1}{2})}^{2}-{(\frac{1}{2})}^{-4}$

${x}^{2}-{x}^{-4}=\frac{1}{4}-(\frac{2}{1})^{4}$

${x}^{2}-{x}^{-4}=\frac{1}{4}-16$

${x}^{2}-{x}^{-4}=\frac{1-64}{4}$

$\boxed{{x}^{2}-{x}^{-4}=-\frac{63}{4}}$