Question

1-indentifique os coeficientes a,b e c nós termos abaixo
a)5x²+3x-2=0
a=______ b=______ c=______
b)-3x²+24x-5=0
a=______ b=______c=______
C)-9x²+6x-5=0
a=______ b=______c=______
d)2x²+3=0
a=______b=______c=_______

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\mathsf{a)\:5x^2 + 3x -2 = 0}\rightarrow\begin{cases}\mathsf{a = 5}\\\mathsf{b = 3}\\\mathsf{c = -2}\end{cases}$

$\mathsf{b)\:-3x^2 + 24x -5 = 0}\rightarrow\begin{cases}\mathsf{a = -3}\\\mathsf{b = 24}\\\mathsf{c = -5}\end{cases}$

$\mathsf{c)\:-9x^2 + 6x -5 = 0}\rightarrow\begin{cases}\mathsf{a = -9}\\\mathsf{b = 6}\\\mathsf{c = -5}\end{cases}$

$\mathsf{d)\:2x^2 + 3 = 0}\rightarrow\begin{cases}\mathsf{a = 2}\\\mathsf{b = 0}\\\mathsf{c = 3}\end{cases}$

Answer 2

• Equação do 2° grau

$\red{\boxed{\sf a {x}^{2} + bx + c}}$

• Comparando as equações:

A)

$5 {x}^{2} + 3x - 2 = 0 \\ \\ \red{\boxed{\sf a = 5 }} \\ \red{\boxed{\sf b = 3 }} \\ \red{\boxed{\sf c - 2 }}$

B)

$- 3 {x}^{2} + 24x - 5 = 0 \\ \\ \red{\boxed{\sf a = - 3 }} \\ \red{\boxed{\sf b = 24}} \\ \red{\boxed{\sf c = - 5 }}$

C)

$- 9 {x}^{2} + 6x - 5 = 0 \\ \\\red{\boxed{\sf a = - 9}} \\ \red{\boxed{\sf b = 6 }} \\ \red{\boxed{\sf c = - 5 }}$

D)

$2 {x}^{2} + 3 = 0 \\ \\ \red{\boxed{\sf a = 2 }} \\ \red{\boxed{\sf b = 0 }} \\ \red{\boxed{\sf c = 3 }}$

espero ter ajudado!