Matemática, perguntado por mariaoliveiracostamo, 5 meses atrás

1) Determine o valor em cada situação
a) sen 960°
b) cos 675°
c) tg 1500°​

Soluções para a tarefa

Respondido por CyberKirito
0

\large\boxed{\begin{array}{l}\tt a)\\\rm 960^\circ|\underline{360^\circ}\\\!\!\!\!-\underline{\rm720^\circ}~~2\\\rm240^\circ\\\rm 960^\circ=2\cdot360^\circ+240^\circ\\\rm sen(960^\circ)=sen(240^\circ)=-sen(60^\circ)\\\rm sen(960^\circ)=-\dfrac{\sqrt{3}}{2}\end{array}}

\large\boxed{\begin{array}{l}\tt b)\\\,\rm 675^\circ|\underline{360^\circ}\\\!\!\!\!\rm-\underline{360^\circ}~~1\\\rm315^\circ\\\\\rm 675^\circ=1\cdot360^\circ+315^\circ\\\\\rm cos(675^\circ)=cos(315^\circ)=-cos(45^\circ)\\\rm cos(675^\circ)=-\dfrac{\sqrt{2}}{2}\end{array}}

\large\boxed{\begin{array}{l}\tt c)\\\rm 1500^\circ|\underline{360^\circ}\\\!\!\!\!-\underline{\rm1440^\circ}~~4\\\rm\,\,\,\,60^\circ\\\\\rm 1500^\circ=4\cdot360^\circ+60^\circ\\\\\rm tg(1500^\circ)=tg(60^\circ)=\sqrt{3}\end{array}}

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