Question

1. Determine as raizes da função definida for fx) = -2° +10x-12.​

Answer 1

Explicação passo-a-passo:

$-2x^2+10x-12=0$

$\Delta=10^2-4\cdot(-2)\cdot(-12)$

$\Delta=100+96$

$\Delta=196$

$x=\dfrac{-10\pm\sqrt{196}}{2\cdot(-2)}$

$x=\dfrac{-10\pm14}{-4}$

$x'=\dfrac{-10+14}{-4}~\longrightarrow~x'=\dfrac{4}{-4}~\longrightarrow~x'=-1$

$x"=\dfrac{-10-14}{-4}~\longrightarrow~x"=\dfrac{-24}{-4}~\longrightarrow~x"=6$