Question

1) Determine:
a) mm.c (3, 4, 6);
b) m.m.c(2 4,8);
c)m.m.c (3, 6, 9);
d)m.m.c (6, 12, 15)​

Answer 1

Resposta:

a) 3,4,6/ 2

3,2,3/2

3,1,3/3

1,3,1

b)24,8/2

12,4/2

6,2/2

3,1/

c)3,6,9/3

1,2,3/2= 2×3x3=18

1,1,3/3

d)6,12,15/3

2,4,5/2

1,2,5/2 = 3x2x2=12

Answer 2

Resposta:

Explicação passo-a-passo:

Para encontrar de cada tripla, devemos decompô-las em fatores primos. Assim:

a)

3, 4, 6 | 2

3, 2, 3 | 2

3, 1, 3 | 3

1, 1, 1 |

m.m.c (3, 4, 6) = 2.2.3 = 12

b)

2, 4, 8 | 2

1, 2, 4 | 2

1, 1, 2 | 2

1, 1, 1 |

m.m.c (2, 4, 8) = 2.2.2 = 8

c)

3, 6, 9 | 2

3, 3, 9 | 3

1, 1, 3 | 3

1, 1, 1 |

m.m.c (3, 6, 9 ) = 2.3.3 = 18

d)

6, 12, 15 | 2

3, 6, 15 | 2

3, 3, 15 | 3

1, 1, 5 | 5

1, 1, 1 |

m.m.c (6, 12, 15) = 2.2.3.5 = 60