Question

1) Dada a função f(x)= -x+2 e g(x)= 2x-1, determine:

 

f(-1) + g(2)

-------------

    f(0)

Answer 1

\$\frac{f(-1)+g(2)}{f(0)}=\frac{-(-1)+2+2.2-1}{2}=\frac{1+2+4-1}{2}=\frac{6}{2}=3$

Answer 2

 f(x)= -x+2  ==> f(-1) = - (-1) + 2 = 1 + 2 = 3

g(x)= 2x-1 ==> g(2) = 2.2 -1 =  3

f(x)= -x+2  ==> f(0) = 0 + 2 =  2 


f(-1) + g(2)
-------------     =   3 + 3  ==> 6 ==> 3
    f(0)                  2           2