Question

1) dada a função afim f (x)=-2x+3, determine:

a) f (1) c) f 1/3

b) f (0) D) f -1/2

2) dada a função afim f(x)=2x+3, determine os valores de x para que :

a) f (x)=1 b) f(x)=0 c) f(x)=1/3

3) dada a função do 1° grau F(x)=(1-5 x ) determinar.

a) f (0) c) f 1/5

b) f (-1)" d) f -1/5

4) considere a função do 1° grau F(x)=-3 x +2. determine os valores de x para que se tenha :

a) F(x)=0 b) F(x)=11

F(x)=-1/2

galera me ajuda ai respondam pfvr .

Answer 1

1)
f (x)=-2x+3

a)
f(1)
-2.1 + 3
-2 + 3
1

b)
f(0)
-2.0 + 3
3

c)
f(1/3)
-2.1/3 + 3
-2/3 + 9/3
7/3

d)
f(-1/2)
-2.(-1/2) + 3
1 + 3
4

2)
f(x)=2x+3

a)
f(x) = 1
2x + 3 = 1
2x = 1 - 3
x = -2/2
x = -1

b)
f(x) = 0
2x + 3 = 0
2x = -3
x = -3/2

c)
f(x) = 1/3
2.x + 3 = 1/3
2x = 1/3 - 3
2x = 1/3 - 9/3
x = -8/3 / 2
x = -8/3 . 1/2
x = -4/3

3)
f(x)=(1-5x)

a)
f(0)
1 - 5.0 = 1

b)
f(-1)
1 - 5. (-1)
1 + 5 = 6

c)
f(1/5)
1 - 5.(1/5)
1 - 1
0

d)
f(-1/5)
1 - 5.(-1/5)
1 + 1
2

4)
f(x)= -3x + 2

a)
f(x) = 0
-3x + 2 = 0
-3x = -2
x = 2/3

b)
f(x) = 11
-3x + 2 = 11
-3x = 11 - 2
x = 9 / -3
x = -3

c)
f(x) = -1/2
-3x + 2 = -1/2
-3x = -1/2 - 2
x = -3/2 / -3
x = -3/2 . -1/3
x = 1/2

=)

Answer 2

$f (x)=-2x+3\\ a) f (1)=-2+3=1\\ b) f (0) =3\\ c) f (1/3)=-( \frac{2}{3})+3= \frac{7}{3} \\\\ d) f (-1/2)=-2 \frac{1} { 2}+3= -1+3=2$]]


$2)f(x)=2x+3\\ a) f (x)=1 \\ 1=2x+3\\ 2x=-2\\ x=-1\\ b) f(x)=0 \\ 0=2x+3\\ x= \frac{-3}{2}$
$c) f(x)=1/3\\\\ \frac{1}{3} =2x+3\\\\ 2x=-3+\frac{1}{3} \\\\ 2x=\frac{-8}{3} \\\\ x=\frac{-8}{6}\\\\ x=\frac{-4}{3}$


$3) F(x)=(1-5 x )\\ a) f (0)\\ f(0)=1\\ b) f (-1)\\ y=6\\ c) f (1/5)\\ y=0\\ d) f (-1/5)\\ y=2$



$4) F(x)=-3 x +2.\\ a) F(x)=0\\ -3x+2=0\\ x= \frac{2}{3}$

$b) F(x)=11\\ -3x+2=11\\ -3x=11-2\\ -3x=9\\ x=-3$

$F(x)=-1/2\\ -3x+2= \frac{-1}{2}\\ -3x=\frac{-1}{2}-2\\\\ -3x=\frac{-5}{2} \\ x= \frac{5}{6}$