Question

1 .Considere o polinômio P(x)=4x^4+3x^3-2x^2+x+k. Sabendo que P(1) = 2, então o valor de P(3) é:

Answer 1

Substituindo P(1) = 2:

$4(1)^{4} +3(1)^{3} -2(1)^{2}+1 +k=2=\ \textgreater \ k= \frac{1}{6}$

Assim, temos:

$4(3)^{4}+3(3)^{3}-2(3)^{2}+3+ \frac{1}{6}+\ \textgreater \ 81+81-18+3+ \frac{1}{6}$
$147+ \frac{1}{6}=\ \textgreater \ \frac{883}{6}$

Answer 2

P(x)=4x⁴+3x³-2x²+x+k
P(3)=4×1²+3×1³-2×1²+3
P(3)=4×1+3×1-2×1+3
P(3)=4+3-2+3=
P(3)=8