Question

usando log2=a log3=b log7=c
calcule:
log35

Answer 1

Propriedades :

log(a.b) = loga + logb

log(a/b) = loga - logb

Calculando log35 :

log35 = log(70/2)

log35 = log70 - log2

log35 = log(7.10) - a

log35 = log7 + log10 - a

log35 = c+1-a