Question

1) Considere a função f(x)=x² + 3x - 6, determine o valor de
f(-1)=
f(-3)=
c) 1
_
2

d) f(0)=
f)o valor de x, para que fique f(x)=-2
e) o valor de x, para que fique f(x)=12

Answer 1

f(-1)= -1^2+3*(-1)-6 -> 1-3-6 -> -2-6 -> -8

f(-3)= -3^2+3*(-3)-6 -> 9-9-6 -> 0-6 -> -6

f(1/2) = 1/2^2+3*1/2-6 -> 1/4 + 3/2 -6 -> 7/4-6 -> -17/4

f(0)= 0^2+3*0-6 -> 0+0-6 -> -6