Question

1. Calcule os valores das potências:
a)62
b) (−6)2
c) −62 d) −23 e) −2−3
f)50
g) (−8)0
h) (3)4 2
i) (3)−1 2
j) (− 3)−3 2
k) 028 l) 112
m) (−1)17 n) (−2)−2
o) 4−2

Answer 1

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$\boxed{\begin{array}{l}\bf 1.~Calcule~os~valores~das~pot\hat encias:\\\rm a)~\sf6^2=6\cdot6=36\\\rm b)~\sf(-6)^2=(-6)\cdot(-6)=36\\\rm c)~\sf-6^2=-(6\cdot6)=-36\\\rm d)~\sf-2^3=-(2\cdot2\cdot2)=-8\\\rm e)~\sf-2^{-3}=-\bigg(\dfrac{1}{2}\bigg)^3=-\bigg[\dfrac{1}{2}\cdot\dfrac{1}{2}\cdot\dfrac{1}{2}\bigg]=-\dfrac{1}{8}\\\rm f)~\sf5^0=1\\\rm g)~\sf(-8)^0=1\\\rm h)~\sf(3^4)^2=3^{4\cdot2}=3^8=6561\\\rm i)~\sf(3^{-1})^2=\bigg(\dfrac{1}{3}\bigg)^2=\dfrac{1}{9}\end{array}}$

$\boxed{\begin{array}{l}\rm j)~\sf[(-3)^{-3}]^2=\bigg[\bigg(-\dfrac{1}{3}\bigg)^3\bigg]^2=\bigg(-\dfrac{1}{3}\bigg)^6=\dfrac{1}{729}\\\rm k)~\sf0^{28}=0\\\rm \ell)~\sf 1^{12}=1\\\rm m)~\sf(-1)^{17}=-1\\\rm n)~\sf(-2)^{-2}=\bigg(-\dfrac{1}{2}\bigg)^2=\dfrac{1}{4}\\\rm o) ~\sf4^{-2}=\bigg(\dfrac{1}{4}\bigg)^2=\dfrac{1}{16}\end{array}}$