1)calcule o quadrado da soma de dois termos:
(2x+1)²=
(3y+3a)² =
(3+x)² =
(2x+3y)² =
2)calcule o quadrado da difrença de dois termos:
(2y-4)² =
(x-2)² =
(3x-2y)² =
(2n-1)² =
Soluções para a tarefa
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Soma:
A)(2x+1)²=
(2x+1).(2x+1) =
4x²+2x+2x+1 =
4x²+4x+1
B)(3y+3a)² =
(3y+3a).(3y+3a) =
9y²+9ya+9ya+9a² =
9y²+18ya+9a²
C)(3+x)² =
(3+x).(3+x) =
9+3x+3x+x² =
9+6x+x² ou x²+6x+9
D)(2x+3y)² =
(2x+3y).(2x+3y) =
4x²+6xy+6xy+9y² =
4x²+12xy+9y²
Subtração:
A)(2y-4)² =
(2y-4).(2y-4) =
4y²-8y-8y+16 =
4y²-16y+16
B)(x-2)² =
(x-2).(x-2) =
x²-2x-2x+4 =
x²-4x+4
C)(3x-2y)² =
(3x-2y).(3x-2y) =
9x²-6xy-6xy+4y² =
9x²-12xy+4y²
D)(2n-1)² =
(2n-1).(2n-1) =
4n²-2n-2n+1
4n²-4n+1
A)(2x+1)²=
(2x+1).(2x+1) =
4x²+2x+2x+1 =
4x²+4x+1
B)(3y+3a)² =
(3y+3a).(3y+3a) =
9y²+9ya+9ya+9a² =
9y²+18ya+9a²
C)(3+x)² =
(3+x).(3+x) =
9+3x+3x+x² =
9+6x+x² ou x²+6x+9
D)(2x+3y)² =
(2x+3y).(2x+3y) =
4x²+6xy+6xy+9y² =
4x²+12xy+9y²
Subtração:
A)(2y-4)² =
(2y-4).(2y-4) =
4y²-8y-8y+16 =
4y²-16y+16
B)(x-2)² =
(x-2).(x-2) =
x²-2x-2x+4 =
x²-4x+4
C)(3x-2y)² =
(3x-2y).(3x-2y) =
9x²-6xy-6xy+4y² =
9x²-12xy+4y²
D)(2n-1)² =
(2n-1).(2n-1) =
4n²-2n-2n+1
4n²-4n+1
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