Question

1- Calcule as potências:

a)${ - 7}^{2}$
b) $( - 5) {}^{2}$
c) ${2}^{5}$
d) $( - 2) {}^{5}$
e)$- ( - 3) {}^{4}$
f) $- 2 {}^{ - 5}$
g) $( - \frac{2}{5}) {}^{3}$
h) $( - \frac{3}{2}) {}^{ - 4}$
i) $( - \frac{1}{2}) {}^{6}$
j) ${6}^{ - 2}$

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Answer 1

Resposta:

Explicação passo a passo:

A) - 7^2 = - 7.7

= - 49

__________

B) (-5)^2 = (-5).(-5)

= + 25

_________

C)

2^5

= 2.2.2.2.2

= 32

________

D)

(-2)^5 = (-2).(-2).(-2).(-2).(-2)

= 4.4.(-2)= 16.(-2)= - 32

= - 32

__________

E)

-(-3)^4

= - [(-3).(-3).(-3).(-3)]

= - [ 9.9]

= - [81]

= - 81

_____________

F)

- 2^(-5)

= (-1/2)^5

= - 1/32

____________

G)

(-2/5)^3

= (-2/5).(-2/5).(-2/5)

= - 8/125

__________________

H)

(-3/2)^(-4)

= (-2/3)^4

= (-2/3).(-2/3).(-2/3).(-2/3)

= 4/9 . 4/9

= 16/81

______________

I)

(-1/2)^6

= (-1/2).(-1/2).(-1/2).(-1/2).(-1/2).(-1/2)

= 1/4 . 1/4 . 1/4

= 1/64

_______________

J)

6^(-2) = (1/6)^2

= 1/6 . 1/6

= 1/36

Answer 2

Resposta:

$-7^2=-49\\\\(-5)^2=+25\\\\2^5=+32\\\\(-2)^5=-32\\\\-(-3)^4=-81\\\\-2^-^5=-\frac{1}{32}\\\\(-\frac{2}{5})^3=-\frac{8}{125}\\\\(-\frac{3}{2})^-^4=\frac{16}{81}\\\\(-\frac{1}{2})^6=\frac{1}{64}\\\\6^-^2=\frac{1}{36}$