Question

1) Calcule as potências: a) 4⁻² = b) 4⁻³ = c) 5⁻¹ = d) 3⁻³ = e) 10⁻² = f) 10⁻³ = g) 2⁻⁵ = h) 7⁻¹ = i) 1⁻¹⁸ = j) (-5)⁻² = k) (-3)⁻⁴ = l) (-2)⁻⁵ = m) (-5)⁻³ = n) (-1)⁻⁴ = o) (-1)⁻⁵ =

Answer 1

Resposta:

Olá!

Explicação passo-a-passo:

1. a) $4^{-2}=(\frac{1}{4})^2=\frac{1}{4} .\frac{1}{4} =\frac{1}{16}$

b) $4^{-3}=(\frac{1}{4})^3=\frac{1}{4} .\frac{1}{4} .\frac{1}{4} =\frac{1}{64}$

c) $5^{-1}=(\frac{1}{5})^1=\frac{1}{5}$

d) $3^{-3}=(\frac{1}{3} )^3=\frac{1}{3} .\frac{1}{3}.\frac{1}{3} =\frac{1}{27}$

e) $10^{-2}=(\frac{1}{10})^2=\frac{1}{10} .\frac{1}{10} =\frac{1}{100}$

f) $10^{-3}=(\frac{1}{10})^3=\frac{1}{10} .\frac{1}{10} .\frac{1}{10} =\frac{1}{1000}$

g) $2^{-5}=(\frac{1}{2})^5=\frac{1}{2} .\frac{1}{2}.\frac{1}{2}.\frac{1}{2}.\frac{1}{2} =\frac{1}{32}$

h) $7^{-1}=(\frac{1}{7})^1=\frac{1}{7}$

i) $1^{-18}=(\frac{1}{1})^{18}= =\frac{1}{1} =1$

j) $(-5)^{-2}=(\frac{1}{(-5)})^2=\frac{1}{-5} .\frac{1}{-5} =\frac{1}{25}$

k) $(-3)^{-4}=(\frac{1}{(-3)})^{4}=\frac{1}{-3}.\frac{1}{-3}.\frac{1}{-3} .\frac{1}{-3}=\frac{1}{81}$

l) $(-2)^{-5}=(\frac{1}{(-2)} )^5=\frac{1}{-2} .\frac{1}{-2} .\frac{1}{-2} .\frac{1}{-2}. \frac{1}{-2} =-\frac{1}{32}$

m) $(-5)^{-3}=(\frac{1}{5} )^3=\frac{1}{-5} .\frac{1}{-5}. \frac{1}{-5} =-\frac{1}{125}$

n) $(-1)^{-4}=(\frac{1}{(-1)})^4=\frac{1}{-1}. \frac{1}{-1} .\frac{1}{-1} .\frac{1}{-1}=\frac{1}{1}=1$

o) $(-1)^{-5}=(\frac{1}{(-1)})^5=\frac{1}{-1}. \frac{1}{-1} .\frac{1}{-1} .\frac{1}{-1}.\frac{1}{-1}=-\frac{1}{1} =-1$

Bons Estudos!