Question

1) Calcule as Massas Moleculares dos Compostos:

a) NO3

b) CaCO3

c) HF

d) MnO​

Answer 1

Resposta:

a)

N= 14×1 = 14

O= 16×3 = 48

NO₃= 14+48 = 62g/mol

b)

Ca= 40×1 = 40

C= 12×1 = 12

O= 16×3 = 48

CaCO₃= 40+12+48 = 100g/mol

c)

H= 1×1 = 1

F= 19×1 = 19

HF= 1+20 = 20g/mol

d)

Mn= 55×1 = 55

O= 16×1 = 16

MnO= 55+16 = 71g/mol

Answer 2

Resposta:

A) NO3 = 62 g/mol

Valores:

N = 14u

O3 = 16u . 3 = 48 u

Total:

14u + 48u = 62 g/mol

B) CaCO3 = 100 g/mol

Valores:

Ca = 40u

C = 12u

O3 = 16u . 3 = 48u

Total:

40u + 12u + 48u = 100 g/mol

C) HF = 20 g/mol

Valores:

H = 1u

F= 19u

Total:

1u + 19u = 20 g/mol

D) MnO = 71 g/mol

Valores:

Mn = 55u

O = 16u

Total:

55u + 16u = 71 g/mol

Espero ter ajudado! :)