Question

1) calcule as divisões de monômios

A) (15x⁶)÷(3x⁴)

B) (16A⁴)÷(8A)

C) (-15x⁸) ÷(3x²)

D) (-10y⁵) ÷ (-2y)

E) (-7abc) ÷(-ab)

F) (-35y⁷) ÷ (5y³)

G) (-12x) ÷ (3y)

H) (8x⁶) ÷ (4x⁴)

I)( 1/3x³) ÷(-1/5x²)

J) (-2xy²) ÷ (xy/4)

URGENTEEE

Answer 1

Resposta:

$A)\\ \\ (15x^{6}):(3x^{4} ) =\frac{15x^{6} }{3x^{4} } =\frac{15}{3} .\frac{x^{6} }{x^{4} } =5x^{6-4} =5x^{2} \\ \\ B)\\ \\ (16a^{4}):(8a ) =\frac{16a^{4} }{a^{1} } =16a^{4-1} =16a^{3}\\ \\ C)\\ \\ (-15x^{8}):(3x^{2} ) =\frac{-15x^{8} }{3x^{2} } =\frac{-15}{3} .\frac{x^{8} }{x^{2} } =-5x^{8-2} =-5x^{6}$

$D)\\ \\ (-10y^{5}):(-2y ) =\frac{-10y^{5} }{-2y^{1} } =\frac{-10}{-2} .\frac{y^{5} }{y^{1} } =5y^{5-1} =5y^{4} \\ \\ E)\\ \\ (-7abc):(-ab)=\frac{ab.(-7c)}{-ab} =-1(-7c)=+7c\\ \\ F)\\ \\ (-35y^{7}):(5y^{3} ) =\frac{-35y^{7} }{5y^{3} } =\frac{-35}{5} .\frac{y^{7} }{y^{3} } =-7y^{7-3} =-7y^{4} \\ \\ G)\\ \\ (-12x):(3y)=\frac{-12}{3} .\frac{x}{y} =-\frac{4x}{y}$

$H)\\ \\ (8x^{6}):(4x^{4} ) =\frac{8x^{6} }{4x^{4} } =\frac{8}{4} .\frac{x^{6} }{x^{4} } =2x^{6-4} =2x^{2} \\ \\ I)\\ \\ (\frac{1}{3x^{3} } ):-(\frac{1}{5x^{2} } )=3x^{-3}:-5x^{-2} =-\frac{3}{5} .x^{-3-(-2)} =-\frac{3x^{-3+2} }{5} \\ \\- \frac{3x^{-1} }{5} =-\frac{3}{5} .\frac{1}{x^{1} } =-\frac{3}{5x} \\ \\ J)\\ \\ (-2xy^{2} ):\frac{xy}{4} =\frac{4.(-2xy^{2} )}{xy} =\frac{-8xy^{2} }{xy} =-8y$