Question

1) calcule a derivada:

y= x^3/2 + 3x/2

Answer 1

$y=x^n\\\\ \large\boxed{y'=n*x^{n-1}}\\ \\ y=\frac{x^3}{2}+\frac{3x}{2}\\\\ y'=\frac{3x^2}{2}+\frac{3}{2}\\\\ \large\boxed{y'=\frac{3}{2}(x^2+1)}$