Question

1 ) Calcule : A ) 20 ⁴√128 ÷ 5 ⁴√4 B ) (2√3 − 3)(2 + √3) C ) ³√32 ÷ ³√8 (obs : é pra hoje )

Answer 1

Explicação passo-a-passo:

a) $\sf \sqrt[4]{128}=\sqrt[4]{4\cdot32}$

Assim:

$\sf 20\sqrt[4]{128}\div5\sqrt[4]{4}=4\sqrt[4]{32}$

b)

$\sf (2\sqrt{3}-3)\cdot(2+\sqrt{3})=4\sqrt{3}+6-6-3\sqrt{3}$

$\sf (2\sqrt{3}-3)\cdot(2+\sqrt{3})=\sqrt{3}$

c) $\sqrt[3]{32}\div\sqrt[3]{8}=\sqrt[3]{8\cdot4}\div\sqrt[3]{8}=\sqrt[3]{4}$