Question

1/7 - 49/27 ÷ (7/3)^3

Answer 1

$\frac{ \frac{1}{7}- \frac{49}{27} }{ (\frac{7}{3})^3 } = \\ \\ =\frac{ \frac{1}{7}- \frac{49}{27} }{ \frac{7^3}{3^3} } = \\ \\ =\frac{ \frac{27-7}{189} }{ \frac{7^3}{3^3} } = \\ \\ =\frac{ \frac{20}{189} }{ \frac{343}{27} } = \\ \\ = \frac{20}{189} . \frac{27}{343} = \\ \\ = \frac{20}{2401}$