Question

1) 6(a-3)=2(a-5)
2)7+2(3y-5)=2(y-5)+13

Answer 1

Oih!!

Resolução:

1)
$6(a - 3) = 2(a - 5) \\ 6a - 18 = 2a - 10 \\ 6a - 2a = - 10 + 18 \\ 4a = 8 \\ a = \frac{8}{4} \\ a = 2$
2)
$7 + 2(3y - 5) = 2(y - 5) + 13 \\ 7 + 6y - 10 = 2y - 10 + 13 \\ 7 + 6y = 2y + 13 \\ 6y - 2y = 13 - 7 \\ 4y = 6 \\ y = \frac{6}{4 } \\ y = \frac{3}{2}$