1+4/X-2=8/X+2=0 desde já agradeço
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Bom dia!
Solução!
![\dfrac{1+4}{x-2}= \dfrac{8}{x+2}\\\\\\\
\dfrac{5}{x-2}= \dfrac{8}{x+2}\\\\\\\
5(x+2)=8(x-2)\\\\\\
5x+10=8x-16\\\\\\\
5x-8x=-16-10\\\\\\
-3x=-26\\\\\
x= \dfrac{-26}{-3}\\\\\\\
\boxed{x=\dfrac{26}{3}}](https://tex.z-dn.net/?f=+%5Cdfrac%7B1%2B4%7D%7Bx-2%7D%3D+%5Cdfrac%7B8%7D%7Bx%2B2%7D%5C%5C%5C%5C%5C%5C%5C%0A+++%5Cdfrac%7B5%7D%7Bx-2%7D%3D+%5Cdfrac%7B8%7D%7Bx%2B2%7D%5C%5C%5C%5C%5C%5C%5C%0A5%28x%2B2%29%3D8%28x-2%29%5C%5C%5C%5C%5C%5C%0A5x%2B10%3D8x-16%5C%5C%5C%5C%5C%5C%5C%0A5x-8x%3D-16-10%5C%5C%5C%5C%5C%5C%0A-3x%3D-26%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-26%7D%7B-3%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Bx%3D%5Cdfrac%7B26%7D%7B3%7D%7D%0A+++ "\dfrac{1+4}{x-2}= \dfrac{8}{x+2}\\\\\\\
\dfrac{5}{x-2}= \dfrac{8}{x+2}\\\\\\\
5(x+2)=8(x-2)\\\\\\
5x+10=8x-16\\\\\\\
5x-8x=-16-10\\\\\\
-3x=-26\\\\\
x= \dfrac{-26}{-3}\\\\\\\
\boxed{x=\dfrac{26}{3}}")
Bom dia!
Bons estudos!
Solução!
Bom dia!
Bons estudos!
cesar100ap:
Obrigado
Porquê o 26 virou 23 aí no fim da conta?
Falta de atenção!
Agora sim!
valeu, ajudou bastante
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