Question

(-1/3)^3 + (3^-1 - (-3)^-1)^-2 alguem pode me ajudar com essa?

Answer 1

$\ \ \ (- \frac{1}{3})^3 + (3^{-1} - (-3)^{-1})^{-2}\\ \\=- \frac{1}{27} + ( \frac{1}{3} - (- \frac{1}{3} ))^{-2}\\ \\=- \frac{1}{27} + ( \frac{1}{3} + \frac{1}{3})^{-2}\\ \\=- \frac{1}{27} + ( \frac{2}{3})^{-2}\\ \\=- \frac{1}{27} + ( \frac{3}{2})^2\\ \\=- \frac{1}{27} + \frac{9}{4}\\ \\=- \frac{4}{108} + \frac{243}{108}\\ \\= \frac{-4+243}{108} \\ \\= \frac{239}{108}$