Question

(1/27)^-x*(3^3x)^2 = (1/3)^x-1

agradeço muito quem me ajudar

Answer 1

(1/27)^-x*(3^3x)^2 = (1/3)^x-1
3^3x . 3^6x =3^-x+1
3^3x+6x = 3^-x+1
3^9x = 3^-x+1
9x=-x+1
9x+x=1
10x=1
x=1/10

Answer 2

(1/27)^-x*(3^3x)^2 = (1/3)^x-1
(1/27)^-x*(3^6x)=(1/3)^x-1
(1/3^3)^-x*(3^6x)=(1/3)^x-1
(3^-3)^-x*(3^6x)=(3^-1)^x-1
(3^-1*-x)*(3^6x)=(3^-1*x-1)
(3^3x)*(3^6x)=3^-x+1
Soma os expoentes
3^3x+6x=3^-x+1
3^9=3^-x+1
Bases iguais logo:
9x=-x+1
9x+x=1
10x=1
x=1/10

Espero ter ajudado