Question

( 1 2/3 )² =

cálcule a potência ?​

Answer 1

(1 2/3)^2 é o mesmo que: (1/1 + 2/3)^2

Agora, tirando o MMC dos DENOMINADORES obtemos o resultado 3

Então dividimos o resultado (3) pelos denominadores e multiplicamos com os numeradores:

3 ÷ 1 = 3 × 1 = 3

3 ÷ 3 = 1 × 2 = 2

Temos (3+2 / 3)^2 = (5/3)^2

Agora resolvendo a potencia:

5 × 5

-------- =

3 × 3

25

------

9

Logo, o resultado da conta é 25/9

Answer 2

$\Large\boxed{\begin{array}{l}\rm dividendo|\underline{divisor}\\\rm quociente~~resto\\\underline{\rm Convers\tilde ao\,de\,frac_{\!\!,}\tilde ao\,impr\acute opria}\\\underline{\rm para\,frac_{\!\!,}\tilde ao\,mista}\\\\\sf\dfrac{dividendo}{divisor}=quociente~\dfrac{resto}{divisor}\\\\\underline{\rm Convers\tilde ao\,de\,frac_{\!\!,}\tilde ao\,mista}\\\underline{\rm para\,frac_{\!\!,}\tilde ao\,impr\acute opria}\\\sf quociente~ \dfrac{resto}{divisor}=\dfrac{ quociente\times divisor+resto}{divisor}\end{array}}$

$\Large\boxed{\begin{array}{l}\sf \bigg(1~\dfrac{2}{3}\bigg)^2\\\rm Aqui\,vamos\,converter\,a\,frac_{\!\!,}\tilde ao\,mista\\\rm em\,impr\acute opria.\\\\\sf 1~\dfrac{2}{3}=quociente~\dfrac{resto}{divisor}\\\begin{cases}\sf quociente=1\\\sf resto=2\\\sf divisor=3\end{cases}\\\sf quociente~\dfrac{resto}{divisor}=\dfrac{quociente\times divisor+resto}{divisor}\\\\\sf 1~\dfrac{2}{3}=\dfrac{1\cdot3+2}{3}=\dfrac{3+2}{3}=\dfrac{5}{3}\\\\\sf DA\acute I\end{array}}$

$\Large\boxed{\begin{array}{l}\sf\bigg(1~\dfrac{2}{3}\bigg)^2=\bigg(\dfrac{5}{3}\bigg)^2=\dfrac{5}{3}\cdot\dfrac{5}{3}\\\\\sf \bigg(1~\dfrac{2}{3}\bigg)^2=\dfrac{5\cdot5}{3\cdot3}=\dfrac{25}{9}\end{array}}$