Question

05) Se Log b de base a =3 e log de c de base ab=4, então log c de base a é:
a) 12 b) 16 c) 24 d) 8 e) 6

Answer 1

Oi Barbara

loga(b) = 3  ⇒ b = a³ 

logab(c) = 4  ⇒ c = a⁴b⁴

log(c) = 4log(a) + 4log(b)
log(c) = 4log(a) + 4*3log(a) 
log(c) = 16log(a)

loga(c) = log(c)/log(a) = 16 (B)

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