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Anexos:
Soluções para a tarefa
Respondido por
1
Bom,i1 é a corrente inicial,portanto é a soma de todas as correntes que se dividiram:
i1 = 3+2+8 = 13 A
Já i2 é a soma das correntes equivalentes a 2 A e a 8A:
i2 = 2+8 = 10 A
i1 = 3+2+8 = 13 A
Já i2 é a soma das correntes equivalentes a 2 A e a 8A:
i2 = 2+8 = 10 A
alvarovcarvalho:
valeu
Respondido por
0
Resposta:
i1 = 3+2+8 = 13 A
i2 = 2+8 = 10 A
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