Question

z1=12+4i e z2 = 3 - 5i​

Answer 1

Resposta:

$z3 = z1*z2 = \\12*3 = 36\\12*5i = 60i\\4i * 3 = 12i\\4i * -5i = -20i^{2} \\-20i^{2}  = 20\\36+60i+12i+20 = 116 + 12i\\z3 = 116 + 12i$

$Adicao\\z3 = z1+z2 = \\12 + 3\\4i +(-5i)\\\\z3 = 15 - 1i\\\\Divisao\\\frac{12 + 4i}{3 - 5i} * \frac{3 + 5i}{3 + 5i} \\\\b = 3^{2} - 5^{2}i^{2}  \\a = 36 + 60i + 12i + 20i^{2} \\\\\frac{16 + 72i}{9 -25}$