Question

y²-6y+9=16 usando a fórmula de Bháskara.

Answer 1

Y^2 - 6y +9 - 16 =0
Y^2 - 6y - 7 =0
Delta = b^2 - 4 x a x c
Delta = (-6)^2 - 4 x 1 x (-7)
Delta = 36 + 28
Delta = 64

Y= - b +- raiz de delta/2 x a
Y= - (-6) +- 64/2
Y= 6 +- 8/2
Y1= 6+8/2 = 14/2 = 7
Y2 = 6-8/2 = -2/2 = - 1

Answer 2

y2 - 6y + 9 = 16
y2 - 6y - 7 = 0
∆ = ( 6 ) 2 - 4•1 • ( -7 )
∆ = 36 + 28
∆= 64

x' = ( 6 + 8 ) / 2
x' = 14 / 2
x' = 7
x" = ( 6 - 8 ) / 2
x" = - 2 / 2
x" = - 1