Question

y2 + 5y + 6 = 0 socorrrrrro.

Answer 1

a= 1
b= 5
c= 6

$delta \: = {b}^{2} - 4ac$
delta = 5^2 - 4.1.6
delta = 25 -24
delta = 1

$y = \: - b \: + - \sqrt{delta}$
y' = -5 + 1
y' = -4

y'' = -5 -1
y'' = -6