Question

y2-4y+4=0 fórmula de bhaskara (delta)

Answer 1

(-4)2 - 4 . 1 . 4=16-16=0

Answer 2

Δ=b²-4.a.c 
Δ=-4y²-4.y2.4=0
Δ=16y-4.y2.4=0
Δ=16y-16.y2=0
Δ=32y-16
√Δ=16
Δ=32
x-b+/- √Δ/2.a 
x-4y+/-√16/2.y2
x'=-4y+32/2.y2
x'=