Question

y=X²-6x+5 me ajudem por favor ​

Answer 1

$\Delta=b^2-4ac\\\Delta=(-6)^2-4(1)(5)\\\Delta= 16\\\\x=\dfrac{-b\pm\sqrt\Delta}{2a}=\dfrac{6\pm\sqrt{16} }{2}\\\\x'=\dfrac{6+4 }{2}=\dfrac{10}{2}=5\\\\x'=\dfrac{6-4 }{2}=\dfrac{2}{2}=1$