Question

y = -x² + 25
Quais são os vertices e raizes da equação acima?

Answer 1

Y = -x² + 25

a= -1

b= 0

c= 25

Delta

Δ=b²-4ac

Δ=0² - 4 * (-1)*25

Δ=0+100

Δ=100

baskara;

x=-b+-√Δ /2a

x=-0+-√100 /2*-1

x=-0+-10 / -2

x'=-0+10 / -2

x'= 10/-2

x'=-5

x''=-0-10/-2

x''=-10/-2

x''= 5

Raizes = {x'= -5 e x''= 5}

-------------------

Xv= -b /2a

Xv= -0 /2*-1

Xv=-0/-2

Xv= 0

--------

Yx= -Δ /4a

Yx= -100 /4*-1

Yx= -100/-4

Yx= 25

( Xv= 0 e Yx= 25)