Question

y elevado a 2-7y+6=0

Answer 1

Resolvendo por Bháskara (ay²+by+c=0):

$y^2-7y+6=0,~sendo: \\ \\ a=1,~b=-7,~c=6 \\ \\ \Delta~=b^2-4.a.c \\ \Delta~=(-7)^2-4.1.6 \\ \Delta~=49-24 \\ \Delta~=25$

$y= \frac{-b\pm \sqrt{\Delta~}}{2.a} \\ y= \frac{7\pm \sqrt{25}}{2.1} \\ y= \frac{7\pm5}{2}$

$y'= \frac{7+5}{2}= \frac{12}{2}=6 \\ \\ y''= \frac{7-5}{2}= \frac{2}{2}=1$