Question

Y=-4x^2+3x=0

Me ajudem por favor, valendo 15 pontos!

Answer 1

$-4x^2+3x=0\\ \\ \\x=\frac{-3\pm\sqrt{3^2-4\cdot(-4)\cdot0}}{2\cdot(-4)}=\frac{-3\pm\sqrt{9+0}}{-8}=\frac{-3\pm\sqrt{9}}{-8}=\frac{-3\pm3}{-8}\\ \\x'=\frac{-3+3}{-8}=\frac{0}{-8}=0\\ \\x''=\frac{-3-3}{-8}=\frac{-6^{:2}}{-8_{:2}}= \frac{3}{4}\\ \\S=\Big\{0,\ \frac{3}{4}\Big\}$