Question

y=(3-x^2)(x^3-x+1)

alguém sabe derivar?

Answer 1

Y=(3-x^2)(x^3-x+1)

$Y=(3-x^2)(x^3-x+1) \\Y=3x^3-3x+3-x^5+x^3-x^2 \\Y=4x^3-3x+3-x^5-x^2$

Espero ter ajudado :)